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同轴电缆的特性阻抗计算
同轴电缆 特性阻抗 拉普拉斯方程 矩形网格
同轴电缆的横截面可以看做是两个同心圆。外圆半径为2,内圆半径为1。外圆上的电势为1,内圆上的电势为0。我们依据这些条件,通过编写matlab程序来计算(i,j)==1&&c3(i,j)<1&&c3(i,j)>0&&c2(i,j)==0&&c4(i,j)==1
dianwei_3(i,j)=1;
elseif c1(i,j)==0&&c2(i,j)==1&&c3(i,j)==1&&c4(i,j)==0
dianwei_3(i,j)=0;
elseif c1(i,j)==0&&c2(i,j)==1&&c3(i,j)==1&&c4(i,j)<1&&c4(i,j)>0
dianwei_3(i,j)=0;
elseif c1(i,j)<1&&c1(i,j)>0&&c2(i,j)==1&&c3(i,j)==1&&c4(i,j)==0
dianwei_3(i,j)=0;
end
end
end
for i=2:(l+1)/2
for j=2:(l+1)/2 %c1(i,j)*c2(i,j)*c3(i,j)*c4(i,j)*(((c3(i,j)*dianwei_3(i,j+1)+c1(i,j)*dianwei_3(i,j-1))/(c1(i,j)*c3(i,j)*(c1(i,j)+c3(i,j))))+((c4(i,j)*dianwei_3(i-1,j)+c2(i,j)*dianwei_3(i+1,j))/(c2(i,j)*c4(i,j)*(c2(i,j)+c4(i,j)))))/((c1(i,j)*c3(i,j))+(c2(i,j)*c4(i,j)));
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if c1(i,j)==1&&c2(i,j)==1&&c3(i,j)<1&&c3(i,j)>0&&c4(i,j)==1
dianwei_4(i,j)=c1(i,j)*c2(i,j)*c3(i,j)*c4(i,j)*(((c3(i,j)*dianwei_3(i,j+1)+c1(i,j))/(c1(i,j)*c3(i,j)*(c1(i,j)+c3(i,j))))+((c4(i,j)*dianwei_3(i-1,j)+c2(i,j)*dianwei_3(i+1,j))/(c2(i,j)*c4(i,j)*(c2(i,j)+c4(i,j)))))/((c1(i,j)*c3(i,j))+(c2(i,j)*c4(i,j)));
elseif c1(i,j)==1&&c2(i,j)<1&&c2(i,j)>0&&c3(i,j)==1&&c4(i,j)==1
dianwei_4(i,j)=c1(i,j)*c2(i,j)*c3(i,j)*c4(i,j)*(((c3(i,j)*dianwei_3(i,j+1)+c1(i,j)*dianwei_3(i,j-1))/(c1(i,j)*c3(i,j)*(c1(i,j)+c3(i,j))))+((c4(i,j)+c2(i,j)*dianwei_3(i+1,j))/(c2(i,j)*c4(i,j)*(c2(i,j)+c4(i,j)))))/((c1(i,j)*c3(i,j))+(c2(i,j)*c4(i,j)));
elseif c1(i,j)<1&&c1(i,j)>0&&c2(i,j)==1&&c3(i,j)==1&&c4(i,j)==1
dianwei_4(i,j)=c1(i,j)*c2(i,j)*c3(i,j)*c4(i,j)*(((c1(i,j)*dianwei_3(i,j-1))/(c1(i,j)*c3(i,j)*(c1(i,j)+c3(i,j))))+((c4(i,j)*dianwei_3(i-1,j)+c2(i,j)*dianwei_3(i+1,j))/(c2(i,j)*c4(i,j)*(c2(i,j)+c4(i,j)))))/((c1(i,j)*c3(i,j))+(c2(i,j)*c4(i,j)));
elseif c1(i,j)==1&&c2(i,j)==1&&c3(i,j)==1&&c4(i,j)<1&&c4(i,j)>0
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